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Math?


xelander
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Now, at school we had a homework, and we had to show how we did it.
I completly forgot about it, so I didn't make it.
Anyways…
If you were doing this math problem, how would you solve it?
It's 397 000% of 375...
How the hell can you find out the answear?!

Edit: I fixed the %, it was the wrong number. :P
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Lets say 375 is 100%. If you want to take the 197 000% of 375 you do like this.
100=375
197 000= ?

Its 197000 x 375 % 100\. The result would be 738 750.
So 197000% of 375 would be 738 750.

x=y
a=b

b is the number you need to find out. a is  the percentage of the number you need to find out. x is always 100 and y is the number you already know, being 100%.
Its a times y divided by x. It works for any percentage.

Oh and here you can prove my result is right:
http://lmgtfy.com/?q=197000%25+of+375

Hope this is what you wanted.
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@Jna:

> Lets say 375 is 100%. If you want to take the 197 000% of 375 you do like this.
> 100=375
> 197 000= ?
>
> Its 197000 x 375 % 100\. The result would be 738 750.
> So 197000% of 375 would be 738 750.
>
> x=y
> a=b
>
> b is the number you need to find out. a is  the percentage of the number you need to find out. x is always 100 and y is the number you already know, being 100%.
> Its a times y divided by x. It works for any percentage.
>
> Oh and here you can prove my result is right:
> http://lmgtfy.com/?q=197000%25+of+375
>
> Hope this is what you wanted.

Thanks, but I accedently kinda wrote wrong number, it was 397 000, not 197 000, sorry, my fault.
Edited the main post.
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@NinjaCat:

> Now, at school we had a homework, and we had to show how we did it.
> I completly forgot about it, so I didn't make it.
> Anyways…
> If you were doing this math problem, how would you solve it?
> It's 397 000% of 375...
> How the hell can you find out the answear?!
>
> Edit: I fixed the %, it was the wrong number. :P

3970 * 375 = 1488750.

Regards,
  Godlord.
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@Admiral:

> Cool!
> Now solve for x:
> ![](http://i44.tinypic.com/qwykqr.png)

Sure:

6 / (X + 5) = 6 / X + 6 / 5
<=> 6 / (X + 5) = 30 / 5X + 6X / 5X
<=> 6 / (X + 5) = (30 + 6X) / 5X
Conditions:
(X + 5) != 0
5X != 0
<=> 30X = (30 + 6X) * (X + 5)
<=> 30X = 30X + 6X2 + 150 + 30X
<=> 0 = 6X2 + 30X + 150
D = 302 - 4 * 6 * 150
D = 900 - 3600
D = -2700
No solutions found.

V = ∅

Regards,
  Godlord.
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@Godlord:

> @Admiral:
>
> > Cool!
> > Now solve for x:
> > ![](http://i44.tinypic.com/qwykqr.png)
>
> Sure:
>
> 6 / (X + 5) = 6 / X + 6 / 5
> <=> 6 / (X + 5) = 30 / 5X + 6X / 5X
> <=> 6 / (X + 5) = (30 + 6X) / 5X
> Conditions:
> (X + 5) != 0
> 5X != 0
> <=> 30X = (30 + 6X) * (X + 5)
> <=> 30X = 30X + 6X2 + 150 + 30X
> <=> 0 = 6X2 + 30X + 150
> D = 302 - 4 * 6 * 150
> D = 900 - 3600
> D = -2700
> No solutions found.
>
> V = ∅
>
> Regards,
>   Godlord.

You just killed the lulz :sad:
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Sweden is to be honest the second worst country on math. :P

@Rodriguez:

> Forshame Ninja. Needing help on such a 2nd grade problem. Now I shall force you to do the following problem!
>
> |
> ![](http://pic.blog.plover.com/tex/integrals.gif) | sec(_x_)9 _dx_ |
>
> No fucking way…
> I don't even klnow what that means!
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The integral is the anti-derivative. Basically when you take a derivative of something such as dx/dy you would come out with an equation that represents the slope of the original graph. Take another dx/dy and you get an equation representing the curvature of that original graph. It is also implemented in physics where, if you derive a function of position in regards to time, you get a function of velocity. Derive that and you get a function of acceleration. Multiply the y-axis values by the mass and then take the integral and you have it's momentum.

Now, integrals represent the area under the curve of a graph. It came about when Newton was trying to find an equation that undid derivatives. The original equation, known as the midpoint rule is:
![](http://tutorial.math.lamar.edu/Classes/CalcI/DefnofDefiniteIntegral_files/eq0004M.gif)
Where i is the subscript of the number for x*, changing by 1 each time, n (the number of x* in the summation) approaches infinity, and (delta)x is the interval of change between X*'s.

Simply put, the integral of secant of x to the ninth power is probably one of the longest simple integrals on the face of the earth. The integral is as follows:

![](http://www2.wolframalpha.com/Calculate/MSP/MSP225199hdie2312c068700001419ebg10b59d890?MSPStoreType=image/gif&s=24&w=494&h=174)

Where sec(x) is the secant function and log(x) is the natural logarithm. I hope this has enlightened all of you. ;D

- Adulese
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I say maths instead of math (sic) and I'm Dutch.

@Rodriguez:

> Same here Robin. There is only one mathematics. Your English logic defies my understanding.
>
> - Adulese

So, why are you saying mathematics instead of mathematic?

Regards,
  Godlord.
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