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Troll under the bridge


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@∙:

> thats no bridge… its a space station
>
> ![](http://suburbanknights.files.wordpress.com/2009/02/death-star-1.jpg)

You just trip and fall over the bridge!
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@∙:

> did you know the possibility of me caring about that is nill
>
> do i get to pass?

Absolutely, Please caryy on your way!
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@Hippoman:

> so do i get to pass?

Answer this simple question and you may pass.

Consider a fixed line AB=4\. Also consider a line CD, such that
AB=CD=4, and that AB is the perpendicular bisector of CD AND CD is the perpendicular bisector of AB.
Now, consider the set of all points P on CD (which there are inifineitely many). For every unique point P, there is a unique point Q such that QBPA is cyclic (all four points lie on a circle).
The set of all possible points Q creates a familiar figure.
What is that figure and what is the area of that figure?
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@Ambard:

> Answer this simple question and you may pass.
>
> Consider a fixed line AB=4\. Also consider a line CD, such that
> AB=CD=4, and that AB is the perpendicular bisector of CD AND CD is the perpendicular bisector of AB.
> Now, consider the set of all points P on CD (which there are inifineitely many). For every unique point P, there is a unique point Q such that QBPA is cyclic (all four points lie on a circle).
> The set of all possible points Q creates a familiar figure.
> What is that figure and what is the area of that figure?

Is it 50.26?
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@[NW:

> [AFRO] Sean link=topic=41073.msg406298#msg406298 date=1237939041]
> Is it 50.26?

I forgot one more condition.

QP is bisected by AB. Thus there are two unique points Q for every P.

Anyways, inifintiely many points P will create a unique figure for P.

What is the figure and what is that area
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