[RANDOM TOPIC] Cool Equation

[Verex]

Ok. I want someone to solve this equation. It is quite easy and only one number works for it.

REQUIREMENTS:
1\. A brain
2\. Basic Math skills
3\. Uhhhh….. I dont really have a #3 sorry.

EQUATION:
35 x z + 500z / 9986z - 556z = z

[Shinabi]

No duh, it's 0

[Keebler Elf]

Is this your math homework…

[westin444]

@Shinabi:

> No duh, it's 0

Can't divide by 0.

@Verex:

> only **one** number works for it.
>
> 35 x z + 500z / 9986z - 556z = z

Are you implying x=z?

[Admiral Refuge]

You can divide by zero, it just equals infinity.

[Godlord]

@Verex:

> Ok. I want someone to solve this equation. It is quite easy and only one number works for it.
>
> REQUIREMENTS:
> 1\. A brain
> 2\. Basic Math skills
> 3\. Uhhhh….. I dont really have a #3 sorry.
>
> EQUATION:
> 35 x z + 500z / 9986z - 556z = z

Learn the proper notation.
(35z + 500z) / (9986z - 556z) = z
Division Condition: 9986z - 556 != 0
<=> 535z = 9430z²
<=> 9430z² - 535z = 0
<=> (9430z - 535) * z = 0
<=> z = 0 and z = 107/1886

Unless you meant:
35z + 500z / 9986z - 556z = z
D.C.: z != 0
<=> -522z + 250/4993 = 0
<=> 522z = 250/4993
<=> z = 125/1303173

Regards,
  Stephan.

[ToshiroHayate]

@Stephan:

> @Verex:
>
> > Ok. I want someone to solve this equation. It is quite easy and only one number works for it.
> >
> > REQUIREMENTS:
> > 1\. A brain
> > 2\. Basic Math skills
> > 3\. Uhhhh….. I dont really have a #3 sorry.
> >
> > EQUATION:
> > 35 x z + 500z / 9986z - 556z = z
>
> Learn the proper notation.
> (35z + 500z) / (9986z - 556z) = z
> Division Condition: 9986z - 556 != 0
> <=> 535z = 9430z²
> <=> 9430z² - 535z = 0
> <=> (9430z - 535) * z = 0
> <=> z = 0 and z = 107/1886
>
> Unless you meant:
> 35z + 500z / 9986z - 556z = z
> D.C.: z != 0
> <=> -522z + 250/4993 = 0
> <=> 522z = 250/4993
> <=> z = 125/1303173
>
> Regards,
>   Stephan.

Did you draw that on your whiteboard?  ;D

[Godlord]

@Toshiro:

> @Stephan:
>
> > @Verex:
> >
> > > Ok. I want someone to solve this equation. It is quite easy and only one number works for it.
> > >
> > > REQUIREMENTS:
> > > 1\. A brain
> > > 2\. Basic Math skills
> > > 3\. Uhhhh….. I dont really have a #3 sorry.
> > >
> > > EQUATION:
> > > 35 x z + 500z / 9986z - 556z = z
> >
> > Learn the proper notation.
> > (35z + 500z) / (9986z - 556z) = z
> > Division Condition: 9986z - 556 != 0
> > <=> 535z = 9430z²
> > <=> 9430z² - 535z = 0
> > <=> (9430z - 535) * z = 0
> > <=> z = 0 and z = 107/1886
> >
> > Unless you meant:
> > 35z + 500z / 9986z - 556z = z
> > D.C.: z != 0
> > <=> -522z + 250/4993 = 0
> > <=> 522z = 250/4993
> > <=> z = 125/1303173
> >
> > Regards,
> >   Stephan.
>
> Did you draw that on your whiteboard?  ;D

Unless the solutions are complex numbers, I am not going to bother.

Regards,
  Stephan.

[Godlord]

Oh, in return can you solve this for me, OP?
2^(x - 1) + 3^(x + 1) = 2^x + 3^x

Regards,
  Stephan.

[Robin]

@Stephan:

> 2^(x - 1) + 3^(x + 1) = 2^x + 3^x

You've solved it yourself. 2^(x - 1) + 3^(x + 1)  equals  2^x + 3^x.

[Godlord]

And what does x equal to, smart arse?

Regards,
  Stephan.

[Robin]

It's a letter of the alphabet. How can it equal anything?

[Godlord]

@Robin:

> It's a letter of the alphabet. How can it equal anything?

I am disappoint, Robin. You are getting an F.

Regards,
  Stephan.

[ToshiroHayate]

@Stephan:

> @Robin:
>
> > It's a letter of the alphabet. How can it equal anything?
>
> I am disappoint, Robin. You are getting an F.
>
> Regards,
>   Stephan.

Robin: Which also doesn't equal anything.

inb4?

[Robin]


[LRgamer]

http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x

ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x

My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…

[Homicidal Monkey]

@Stephan:

> 2^(x - 1) + 3^(x + 1) = 2^x + 3^x

I am disappoint; expected something more challenging than logs
better equation:
Prove P=NP

@Crispus:

> http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x
>
> ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x
>
> My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…

why would you NOT use natural log?

[LRgamer]

@Zetta:

> @Stephan:
>
> > 2^(x - 1) + 3^(x + 1) = 2^x + 3^x
>
> I am disappoint; expected something more challenging than logs
> better equation:
> Prove P=NP
>
> @Crispus:
>
> > http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x
> >
> > ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x
> >
> > My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…
>
> why would you NOT use natural log?

I would rather use 10 log, much easier on your TI-84, but I guess that scientists rather use ln x

[Homicidal Monkey]

@Crispus:

> @Zetta:
>
> > @Stephan:
> >
> > > 2^(x - 1) + 3^(x + 1) = 2^x + 3^x
> >
> > I am disappoint; expected something more challenging than logs
> > better equation:
> > Prove P=NP
> >
> > @Crispus:
> >
> > > http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x
> > >
> > > ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x
> > >
> > > My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…
> >
> > why would you NOT use natural log?
>
> I would rather use 10 log, much easier on your TI-84, but I guess that scientists rather use ln x

what kind of ghetto calculator does NOT support natural log? its usually something like 2nd e
also: TI-84 is shit. > [link related](http://xkcd.com/768/)

fyi: dont buy graphing calculators for school. You cannot use them on tests/in class and they're expensive and are shit (hardware wise) Instead, learn how to use Open Office Math/Calc and google math for homework. This semester, I didn't even bring a calculator onto campus. (All classes are Math heavy)

[Godlord]

Teachers enforce usage of the TI-84+ over here. Otherwise I'd be using Linux Ubuntu, OpenOffice.org, Calculator and Wolfram Alpha on a laptop.

Regards,
  Stephan.

[LRgamer]

@Zetta:

> @Crispus:
>
> > @Zetta:
> >
> > > @Stephan:
> > >
> > > > 2^(x - 1) + 3^(x + 1) = 2^x + 3^x
> > >
> > > I am disappoint; expected something more challenging than logs
> > > better equation:
> > > Prove P=NP
> > >
> > > @Crispus:
> > >
> > > > http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x
> > > >
> > > > ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x
> > > >
> > > > My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…
> > >
> > > why would you NOT use natural log?
> >
> > I would rather use 10 log, much easier on your TI-84, but I guess that scientists rather use ln x
>
> what kind of ghetto calculator does NOT support natural log? its usually something like 2nd e
> also: TI-84 is shit. > [link related](http://xkcd.com/768/)
>
> fyi: dont buy graphing calculators for school. You cannot use them on tests/in class and they're expensive and are shit (hardware wise) Instead, learn how to use Open Office Math/Calc and google math for homework. This semester, I didn't even bring a calculator onto campus. (All classes are Math heavy)

Yea, it has ln on it, but we normally use the common/decadic logarithm a lot more, I don't know why, but it has something to do with the calculator I guess. I don't mind either form.