Verex Posted December 22, 2010 Author Share Posted December 22, 2010 Ok. I want someone to solve this equation. It is quite easy and only one number works for it.REQUIREMENTS:1\. A brain2\. Basic Math skills3\. Uhhhh….. I dont really have a #3 sorry.EQUATION:35 x z + 500z / 9986z - 556z = z Link to comment Share on other sites More sharing options...
Shinabi Posted December 23, 2010 Share Posted December 23, 2010 No duh, it's 0 Link to comment Share on other sites More sharing options...
Keebler Elf Posted December 23, 2010 Share Posted December 23, 2010 Is this your math homework… Link to comment Share on other sites More sharing options...
westin444 Posted December 23, 2010 Share Posted December 23, 2010 @Shinabi:> No duh, it's 0Can't divide by 0.@Verex:> only **one** number works for it.> > 35 x z + 500z / 9986z - 556z = zAre you implying x=z? Link to comment Share on other sites More sharing options...
Admiral Refuge Posted December 23, 2010 Share Posted December 23, 2010 You can divide by zero, it just equals infinity. Link to comment Share on other sites More sharing options...
Godlord Posted December 23, 2010 Share Posted December 23, 2010 @Verex:> Ok. I want someone to solve this equation. It is quite easy and only one number works for it.> > REQUIREMENTS:> 1\. A brain> 2\. Basic Math skills> 3\. Uhhhh….. I dont really have a #3 sorry.> > EQUATION:> 35 x z + 500z / 9986z - 556z = zLearn the proper notation.(35z + 500z) / (9986z - 556z) = zDivision Condition: 9986z - 556 != 0<=> 535z = 9430z²<=> 9430z² - 535z = 0<=> (9430z - 535) * z = 0<=> z = 0 and z = 107/1886Unless you meant:35z + 500z / 9986z - 556z = zD.C.: z != 0<=> -522z + 250/4993 = 0<=> 522z = 250/4993<=> z = 125/1303173Regards, Stephan. Link to comment Share on other sites More sharing options...
ToshiroHayate Posted December 23, 2010 Share Posted December 23, 2010 @Stephan:> @Verex:> > > Ok. I want someone to solve this equation. It is quite easy and only one number works for it.> > > > REQUIREMENTS:> > 1\. A brain> > 2\. Basic Math skills> > 3\. Uhhhh….. I dont really have a #3 sorry.> > > > EQUATION:> > 35 x z + 500z / 9986z - 556z = z> > Learn the proper notation.> (35z + 500z) / (9986z - 556z) = z> Division Condition: 9986z - 556 != 0> <=> 535z = 9430z²> <=> 9430z² - 535z = 0> <=> (9430z - 535) * z = 0> <=> z = 0 and z = 107/1886> > Unless you meant:> 35z + 500z / 9986z - 556z = z> D.C.: z != 0> <=> -522z + 250/4993 = 0> <=> 522z = 250/4993> <=> z = 125/1303173> > Regards,> Stephan.Did you draw that on your whiteboard? ;D Link to comment Share on other sites More sharing options...
Godlord Posted December 23, 2010 Share Posted December 23, 2010 @Toshiro:> @Stephan:> > > @Verex:> > > > > Ok. I want someone to solve this equation. It is quite easy and only one number works for it.> > > > > > REQUIREMENTS:> > > 1\. A brain> > > 2\. Basic Math skills> > > 3\. Uhhhh….. I dont really have a #3 sorry.> > > > > > EQUATION:> > > 35 x z + 500z / 9986z - 556z = z> > > > Learn the proper notation.> > (35z + 500z) / (9986z - 556z) = z> > Division Condition: 9986z - 556 != 0> > <=> 535z = 9430z²> > <=> 9430z² - 535z = 0> > <=> (9430z - 535) * z = 0> > <=> z = 0 and z = 107/1886> > > > Unless you meant:> > 35z + 500z / 9986z - 556z = z> > D.C.: z != 0> > <=> -522z + 250/4993 = 0> > <=> 522z = 250/4993> > <=> z = 125/1303173> > > > Regards,> > Stephan.> > Did you draw that on your whiteboard? ;DUnless the solutions are complex numbers, I am not going to bother.Regards, Stephan. Link to comment Share on other sites More sharing options...
Godlord Posted December 23, 2010 Share Posted December 23, 2010 Oh, in return can you solve this for me, OP?2^(x - 1) + 3^(x + 1) = 2^x + 3^xRegards, Stephan. Link to comment Share on other sites More sharing options...
Robin Posted December 23, 2010 Share Posted December 23, 2010 @Stephan:> 2^(x - 1) + 3^(x + 1) = 2^x + 3^xYou've solved it yourself. 2^(x - 1) + 3^(x + 1) equals 2^x + 3^x. Link to comment Share on other sites More sharing options...
Godlord Posted December 23, 2010 Share Posted December 23, 2010 And what does x equal to, smart arse?Regards, Stephan. Link to comment Share on other sites More sharing options...
Robin Posted December 23, 2010 Share Posted December 23, 2010 It's a letter of the alphabet. How can it equal anything? Link to comment Share on other sites More sharing options...
Godlord Posted December 23, 2010 Share Posted December 23, 2010 @Robin:> It's a letter of the alphabet. How can it equal anything?I am disappoint, Robin. You are getting an F.Regards, Stephan. Link to comment Share on other sites More sharing options...
ToshiroHayate Posted December 23, 2010 Share Posted December 23, 2010 @Stephan:> @Robin:> > > It's a letter of the alphabet. How can it equal anything?> > I am disappoint, Robin. You are getting an F.> > Regards,> Stephan.Robin: Which also doesn't equal anything.inb4? Link to comment Share on other sites More sharing options...
Robin Posted December 23, 2010 Share Posted December 23, 2010 ![](http://img145.imageshack.us/img145/5022/fuckingmaths.png) Link to comment Share on other sites More sharing options...
LRgamer Posted December 24, 2010 Share Posted December 24, 2010 http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^xln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = xMy ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though… Link to comment Share on other sites More sharing options...
Homicidal Monkey Posted December 25, 2010 Share Posted December 25, 2010 @Stephan:> 2^(x - 1) + 3^(x + 1) = 2^x + 3^xI am disappoint; expected something more challenging than logsbetter equation:Prove P=NP@Crispus:> http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x> > ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x> > My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…why would you NOT use natural log? Link to comment Share on other sites More sharing options...
LRgamer Posted December 25, 2010 Share Posted December 25, 2010 @Zetta:> @Stephan:> > > 2^(x - 1) + 3^(x + 1) = 2^x + 3^x> > I am disappoint; expected something more challenging than logs> better equation:> Prove P=NP> > @Crispus:> > > http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x> > > > ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x> > > > My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…> > why would you NOT use natural log?I would rather use 10 log, much easier on your TI-84, but I guess that scientists rather use ln x Link to comment Share on other sites More sharing options...
Homicidal Monkey Posted December 26, 2010 Share Posted December 26, 2010 @Crispus:> @Zetta:> > > @Stephan:> > > > > 2^(x - 1) + 3^(x + 1) = 2^x + 3^x> > > > I am disappoint; expected something more challenging than logs> > better equation:> > Prove P=NP> > > > @Crispus:> > > > > http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x> > > > > > ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x> > > > > > My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…> > > > why would you NOT use natural log?> > I would rather use 10 log, much easier on your TI-84, but I guess that scientists rather use ln xwhat kind of ghetto calculator does NOT support natural log? its usually something like 2nd ealso: TI-84 is shit. > [link related](http://xkcd.com/768/)fyi: dont buy graphing calculators for school. You cannot use them on tests/in class and they're expensive and are shit (hardware wise) Instead, learn how to use Open Office Math/Calc and google math for homework. This semester, I didn't even bring a calculator onto campus. (All classes are Math heavy) Link to comment Share on other sites More sharing options...
Godlord Posted December 26, 2010 Share Posted December 26, 2010 Teachers enforce usage of the TI-84+ over here. Otherwise I'd be using Linux Ubuntu, OpenOffice.org, Calculator and Wolfram Alpha on a laptop.Regards, Stephan. Link to comment Share on other sites More sharing options...
LRgamer Posted December 26, 2010 Share Posted December 26, 2010 @Zetta:> @Crispus:> > > @Zetta:> > > > > @Stephan:> > > > > > > 2^(x - 1) + 3^(x + 1) = 2^x + 3^x> > > > > > I am disappoint; expected something more challenging than logs> > > better equation:> > > Prove P=NP> > > > > > @Crispus:> > > > > > > http://www.wolframalpha.com/input/?I=2^%28x+-+1%29+%2B+3^%28x+%2B+1%29+%3D+2^x+%2B+3^x> > > > > > > > ln 4 / (ln 2 - ln 3), assuming that ln x = y <=> e^y = x> > > > > > > > My ass is too lazy to solve it algebraically. I have no clue as to why they would use e as base number though…> > > > > > why would you NOT use natural log?> > > > I would rather use 10 log, much easier on your TI-84, but I guess that scientists rather use ln x> > what kind of ghetto calculator does NOT support natural log? its usually something like 2nd e> also: TI-84 is shit. > [link related](http://xkcd.com/768/)> > fyi: dont buy graphing calculators for school. You cannot use them on tests/in class and they're expensive and are shit (hardware wise) Instead, learn how to use Open Office Math/Calc and google math for homework. This semester, I didn't even bring a calculator onto campus. (All classes are Math heavy)Yea, it has ln on it, but we normally use the common/decadic logarithm a lot more, I don't know why, but it has something to do with the calculator I guess. I don't mind either form. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now