C++ epic win!

[Admiral Refuge]

_NOTE: There should be a "Programming Discussion" board or something like that!_

Okay, maybe not an EPIC win, but I did use only notepad, and I did manage to do it WITHOUT google…

My professor challenged me to swap two variables (x and y) in c++; simple right?
int temp;
x = temp;
x = y;
y = temp;

Yea, but he said to do it without using a 3rd variable XD

So, about 2-3 mins on my TI-89 (best calculator in the world!), I figured it out, and wrote this program in 5 mins (notepad ftw!):
```
//Swapping two values without a 3rd.
//Algorithm made by Anthony Ianozi
//Written in Notepad ;)
//Epic win!
#include using namespace std;
/*Declare functions*/
void swap(double&, double&); // Swaps two numbers.
void getNumbers(double&, double&); //Gets two numbers.
void displayNumbers(double, double); //Displays two numbers.
int main()
{
  double x, y;
  getNumbers(x, y);
  cout << "Before swap:\n";
  displayNumbers(x, y);
  swap(x, y);
  cout << "After swap:\n";
  displayNumbers(x, y);
  return 0;
}
void swap(double& a, double& b)
{
/* Let's assume a=5; b=2; */
  if (a > b)
  {
      a = a - b; //a holds 3
      b = b + a; //b holds 5
      a = b - a; //a holds 2
  }
  else
  {
      b = b - a; //b holds 3
      a = a + b; //a holds 5
      b = a - b; //b holds 2
  }
}
void displayNumbers(double first, double second)
{
  cout << "First variable holds " << first << " and variable number holds " << second << ".\n";
}
void getNumbers(double& ex, double& why)
{
  cout << "Hello! Please type two numbers, seperating them with a space, and hit enter.\n";
  cin >> ex >> why;
}
```
I'll just pick out the part where it swaps them:
```
void swap(double& a, double& b)
{
/* Let's assume a=5; b=2; */
  if (a > b)
  {
      a = a - b; //a holds 3
      b = b + a; //b holds 5
      a = b - a; //a holds 2
  }
  else
  {
      b = b - a; //b holds 3
      a = a + b; //a holds 5
      b = a - b; //b holds 2
  }
}
```
:azn:

[xeross]

Haha, win

Regards, Xeross

[vrage]

lol I've come across this method a lot, never used it, its a waste of time and it doesnt work for all data types

[Admiral Refuge]

@V-Rage:

> lol I've come across this method a lot, never used it, its a waste of time and it doesnt work for all data types

You're talking to someone who figured out how to solve square roots to any decimal with just a pencil and paper.

It was just a nice (pretty easy) puzzle to solve; it makes you think, and keeps your brain young :)

[vrage]

@ÅÐмiядζ:

> You're talking to someone who figured out how to solve square roots to any decimal with just a pencil and paper.
>
> It was just a nice (pretty easy) puzzle to solve; it makes you think, and keeps your brain young :)

so, found out whats the square root of -2 yet?
(without using i as an imaginary integer constant)
:P

[Admiral Refuge]

@V-Rage:

> so, found out whats the square root of -2 yet?
> (without using i as an imaginary integer constant)
> :P

No, but I can divide-by-zero XD

[vrage]

@ÅÐмiядζ:

> No, but I can divide-by-zero XD

you beat me there :(

[xeross]

i can too, the answer is infinity

Regards, Xeross

[Homicidal Monkey]

ya do realize that there is a third variable when you have a function? The result is copied into RAM first.

[xeross]

just move everything from the function to the main.

Regards, Xeross

[Skell]

@Xeross:

> i can too, the answer is infinity
>
> Regards, Xeross

You are just like my fellow students on my school, they also believe it is possible to do both 0 / x and y / 0

[Doomsalad]

lol nice. It's always fun doing one of these once in a while

~ :icon_beer:

[Marsh]

a = a^b
b= a^b
a= a^b

[xeross]

@marsh: i've got the feeling that ain't working

Regards, Xeross